The acceleration due to gravity decreases if

$\to$ we go down from the surface of the earth towards its centre then g

decreases $g^1=g\left(1-\frac{\text{d}}{\text{R}}\right)$

$\to$ we go up from the surface of the earth then$g^1=g\left(1-\frac{\text{2h}}{\text{R}}\right)$  and g decreases

$\to$ we go from the equator to towards the pole then g increase$g^1=g-R{\omega }^2{\text{cos}}^2\theta$                 

$\to$ The rotational speed of the earth is increased g decreases

$g^1=g-R{\omega }^2{\text{cos}}^2\theta$