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The average resisting force that must act on a body mass 2kg to reduce its speed from $40 m s^{- 1}$ to $10 m s^{- 1}$ in 0.6s is

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12.5 N

25 N

50 N

100 N

answer is D.

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Detailed Solution

Ft = m (v – u)

$F (0.6) = 2 (40 - 10)$

F = 100N

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