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The condition that the product of two roots $x^{3} + p x^{2} + q x + r = 0$ is –1, is

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$r^{2} + p r + q + 1 = 0$

$q^{2} + p q + q + 1 = 0$

$p^{2} + p q + p + 1 = 0$

$r^{2} - p r - q + 1 = 0$

answer is A.

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Detailed Solution

$α β = - 1, α β γ = - r \Rightarrow γ = r$

$f (r) = 0 \Rightarrow r^{2} + p r + q + 1 = 0$

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