The correct statements about $N{H}_3$ and $N_2{H}_4$ is/are

$N_2{H}_4$is less basic than$N{H}_3$since one of the hydrogen atom is replaced by more electronegative nitrogen atom. The nitrogen atoms in both $N{H}_3$and $N_2{H}_4$are involved in $s{p}^3$hybridization, but HNH bond angles changes due to the difference in the surrounding atoms. $N{H}_3$is a weaker reducing agent than $N_2{H}_4$.