The distance of planet jupiter from the sun is 5.2 times that of the earth. Find the period of revolution of jupiter around the sun

Given that                                

${\text{T}}_{\text{1}}=1\text{year}{\text{T}}_{\text{2}}=?$

${\text{R}}_{\text{1}}=\text{R}{\text{R}}_{\text{2}}=5.2\text{R}$

$\Rightarrow {\left(\frac{{\text{T}}_{\text{1}}}{{\text{T}}_{\text{2}}}\right)}^2={\left(\frac{{\text{R}}_{\text{1}}}{{\text{R}}_{\text{2}}}\right)}^3$                                                      

${\left(\frac{{\text{T}}_{\text{2}}}{{\text{T}}_{\text{1}}}\right)}^2={\left(\frac{{\text{R}}_{\text{2}}}{{\text{R}}_{\text{1}}}\right)}^3$                                                          

$\Rightarrow {\text{T}}_{\text{2}}^{\text{2}}={\left(\frac{{\text{R}}_{\text{2}}}{{\text{R}}_{\text{1}}}\right)}^3{\text{T}}_{\text{1}}^{\text{2}}$

$={\left(\frac{\text{5}\text{.2R}}{\text{R}}\right)}^3\times 1$

${\text{T}}_{\text{2}}=\sqrt{140.6}$                           

${\text{T}}_{\text{2} }=\text{11}.\text{86 years}$