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The equation whose roots are numerically equal but opposite in sign of the roots of $2 x^{2} - 3 x - 2 = 0$

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3 x^{2} - 2 x - 3 = 0

2 x^{2} + 3 x - 2 = 0

3 x^{2} + 2 x + 3 = 0

2 x^{2} + 3 x + 2 = 0

answer is A.

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Detailed Solution

Let

- α = x

$\Rightarrow α = - x$

$\Rightarrow f (- x) = 0$

$\Rightarrow 2 {(- x)}^{2} - 3 (- x) - 2 = 0$

$\Rightarrow 2 x^{2} + 3 x - 2 = 0$

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