The equivalent weight of KCl is

Charge on ${\text{K}}^{+}\left(\text{or}\right)\text{C}{l}^{-}=1$

$\text{Eq}\text{.wt}\text{of}\text{KC}l=\frac{\text{Formula}\text{weight}\text{of}\text{KC}l}{\text{Total charge}\text{on}\text{cation}\text{(or)}\text{anion}}$

$=\frac{74.5}{1}$

$\therefore$ Equivalent weight of KCl is 74.5.