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Q.

The gravitational potential at centre of earth is

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a

\frac{3GM}{2R}

b

- \frac{GM}{2R}

c

- \frac{2GM}{R}

d

- \frac{3GM}{2R}

answer is B.

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Detailed Solution

We know gravitational potential energy of mass m kept at centre of earth is

G .P .E = \frac{- 3 GMm}{2R}

Now gravitational potential

$U = \frac{G .P .E}{m} = \frac{\frac{- 3 GMm}{2R}}{m}$

$∴ U = \frac{- 3 GM}{2 R}$

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