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Q.

The heat energy required to raise the temperature of 2 kg of water from $10 ° C$ to $50 ° C$ is (Specific heat capacity of water is $420 {Jkg}^{- 1} ° C^{- 1}$ )

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a

336 \times 10^{2} J

b

336 \times 10^{4} J

c

336 \times 10^{5} J

d

336 \times 10^{3} J

answer is B.

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Detailed Solution

Given that

$m = 2 kg, Δ t = 50 - 10 = 40 ° C$

$S_{w} = 4200 {JKg}^{- 1} ° C^{- 1}, Q = ?$

$Q = ms Δ t$

$= 2×4200×40$

$= 336000$

$Q = 336 \times 10^{3} J$

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