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Q.

The L.C.M of x2−10x+24,x2−8x+12  and x2−6x+8  is

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a

(x+6)(x+4)(x+2)

b

(x−6)(x−4)(x−2)

c

(x−6)(x−4)(x+2)

d

(6−x)(x+4)(x−2)

answer is A.

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Detailed Solution

x2−10x+24=x2−4x−6x+24⇒(x−4)(x−6)

x2−8x+12=x2−2x−6x+12⇒(x−2)(x−6)

x2−6x+8=x2−2x−4x+8⇒(x−2)(x−4)

L.C.M=(x−6)(x−4)(x−2)

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