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The L.C.M of $x^{2} - 10 x + 24, x^{2} - 8 x + 12$ and $x^{2} - 6 x + 8$ is

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(x + 6) (x + 4) (x + 2)

(x - 6) (x - 4) (x - 2)

(x - 6) (x - 4) (x + 2)

(6 - x) (x + 4) (x - 2)

answer is A.

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Detailed Solution

x^{2} - 10 x + 24 = x^{2} - 4 x - 6 x + 24 \Rightarrow (x - 4) (x - 6)

$x^{2} - 8 x + 12 = x^{2} - 2 x - 6 x + 12 \Rightarrow (x - 2) (x - 6)$

$x^{2} - 6 x + 8 = x^{2} - 2 x - 4 x + 8 \Rightarrow (x - 2) (x - 4)$

L.C.M $= (x - 6) (x - 4) (x - 2)$

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