The normality of $1{\text{M H}}_{\text{3}}{\text{PO}}_{\text{3}}$  solution is

The relation between normality (N) and molarity (M) as follows below.

                        $\text{N}\text{=}\text{n × M}$

Here, n is basicity of an acid. For ${\text{H}}_3{\text{PO}}_{\text{3}}$ , $\text{n}\text{=}\text{2}$

Because there are only 2 “H atoms” can replaceable in${\text{H}}_3{\text{PO}}_{\text{3}}$  .

Concentration of ${\text{H}}_3{\text{PO}}_{\text{3}}$ ,M $\text{=1M}$

Therefore,$\text{normality}\text{= 2}\times \text{1}\text{=}\text{2}\text{N}$