Q.

The number of irrational terms in the expansion of (58+26)100  is

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a

96

b

99

c

97

d

98

answer is A.

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Detailed Solution

tr+1=C  100 r(58)100r.(26)r 

 As 2 and 5 are coprime, tr+1  will be rational if 100r  is a multiple of 8 and r  is a multiple of 6. also 0r100 

r=0,6,12,.....,96  100r=4,10,16,....,100  But 100r  is to be a multiple of 8. So, 100r=0,8,16,24,...96. 

 The common terms in (1) and (2) are 16,40,64  and 88 . r=84,60,36,12  give rational terms.

  The number of irrational terms =1014=97 .

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