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Q.

The number of ways of arranging 8 men and 4 women around a circular table such that no two women sit together is

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a

$8!$

b

$4!$

c

$8! 4!$

d

$7!^{8} P_{4}$

answer is D.

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Detailed Solution

= 7! ${}^{8}P_{4}$

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