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Q.

The parallel sides of a trapezium are $6 c m$ and $8 c m$ . If the distance between
them is $4 c m$ , its area is

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a

42 s q . c m

b

82 s q . c m

c

24 s q . c m

d

28 s q . c m

answer is A.

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Detailed Solution

Given

a = 6 c m, b = 8 c m, h = 4 c m

Area of trapezium $= \frac{1}{2} (a + b) h$

$= \frac{1}{2} (6 + 8) \times 4$

$= \frac{1}{2} (14) \times 4$

$= 28 c m^{2}$

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