Q.

The period of a simple pendulum is found to increase by50% when the length of the pendulum is increased by 0.6m. Calculate the initial length and the initial period of oscillation at a place whereg=9.8m/s2 .

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a

0.28m, 1.491sec

b

0.48m, 1.391sec

c

0.68m, 1.141sec

d

0.18m, 1.451sec

answer is D.

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Detailed Solution

T1=100;T2=150;l1=l;l2=1+0.6

T=2πlg=Tl

T1T2=l1l2

100150=ll+0.6

l=2450=0.48m

T=2π0.489.8

T=1.391sec

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