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The plane faces of two identical Plano convex lenses, each having focal length of 40cm ,are placed against each other to form a usual convex lens .the distance from this lens at which an object must be placed to obtain a real ,inverted image with magnification one is

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$20 c m$

$40 c m$

$160 c m$

$80 c m$

answer is B.

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Detailed Solution

$f_{1} = 40 c m, f_{2} = 40 c m$

From $\frac{1}{F} = \frac{1}{f_{1}} + \frac{1}{f_{2}} = \frac{1}{40} + \frac{1}{40} = \frac{1}{20}$

$F = 20 c m .$

For real, inverted image with unit magnification

$u = R = 2 F = 40 c m .$

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