The product of two numbers is $132x^2$ . If one number is $12x$ then the other is   

Given number=$12x$

Let the other be$\text{'}y\text{'}$

According to the problem

$\left(12x\right)\times y=132x^2$

$\begin{array}{c}y=\frac{132x^2}{12x}\\ y=11x\end{array}$

$\therefore$ Required number is $11x$