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The ratio of the specific charge (e/m) of a proton to that of an $α$ particle is

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1 : 1/4

1 : 4

1 : 2

1 : 1/2

answer is D.

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Detailed Solution

H \to \frac{e}{m} = \frac{Charge of proton}{Mass of proton} = 1

${He}^{+ 2} \to \frac{e}{m} = \frac{Charge of prton + charge of neutron}{Mass of protons + mass of neutrons} = \frac{2}{4} = \frac{1}{2}$ $∴ 1 : \frac{1}{2}$

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