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The resultant R of two forces acting on a particle is at right angles to one of them and its magnitude is one of the other forces. The ratio of larger force to smaller one is:

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2:1

$3 : \sqrt{2}$

3:2

$\sqrt{2} : 1$

answer is D.

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Detailed Solution

If resultant is perpendicular to one of the vector then

$magnitude of the resultant R = \sqrt{Q^{2} - P^{2}} where Q is the larger vector here R = P so 2 R^{2} = Q^{2} \frac{Q}{R} = \frac{\sqrt{2}}{1} = \frac{Q}{P}$

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