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Q.

The transformed equation of x36x2+5x+8=0 by eliminating second term is

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a

x3+7x+2=0

b

x37x+2=0

c

x3+5x+2=0

d

x35x+2=0

answer is B.

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Detailed Solution

h =2

Then the transformed equation in x37x+2=0                                         

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