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Q.

The two thigh bones (femurs), each of cross sectional area $10 c m^{2}$ support the upper part of a human body of mass 40kg. The average pressure sustained by the femurs is

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a

$2 \times 10^{5} N / m^{2}$

b

$3 \times 10^{5} N / m^{2}$

c

$5 \times 10^{5} N / m^{2}$

d

$6 \times 10^{5} N / m^{2}$

answer is B.

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Detailed Solution

$P = \frac{F}{2 A} = \frac{m g}{2 A} = \frac{40 \times 10}{2 \times 10^{- 3}} = 2 \times 10^{5} p a$

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