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Q.

The value of the parameter α,  for which the function f(x)=1+αx,α≠0  is the inverse of itself, is

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a

−2

b

2

c

−1

d

1

answer is B.

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Detailed Solution

f(x)=f−1(x)=f{f(x)}=x

⇒(1+α)=x(1−α2)

∴  it is satisfied only for α=−1

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