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The volume of carbon dioxide obtained by the reaction of $2.12 g$ of ${Na}_{2} {CO}_{3}$ with dil. HCl at STP is

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0.448 ml

4.48 L

44.8 L

0.448 L

answer is C.

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Detailed Solution

{Na}_{2} {CO}_{3} + 2 HCl \to 2 NaCl + H_{2} O + {CO}_{2}

$106 g ----- 22 .4 lit of {CO}_{2}$

$2 .12g ------ ?$

$\frac{2.12}{106} \times 22.4 = 0.448 L$

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