The 10th common term between the series 3+7+11+.. and 1+6+11+… is

The common differences of the two series are 4 and 5 respectively.   

The series of common terms will form an A.P with common difference 20 and first term 11.  ( l.c.m of 4 and 5 is 20 , which is the common difference of the required A.P)

${\text{T}}_{\text{10}}\text{=a+(n-1)d=11+(10-1)}\times \text{20=191}$