The 10th common term between the series $3+7+11+\dots .\text{ and }1+6+11+\dots .$ is.

The first common term is 11. Now the next common term is obtained by adding L.C.M. of the common difference 4 and 5, i.e., 20.

Therefore ${10}^{th}$ common term = $T_{10}$ of the AP whose $a=11\text{ and }d=20$

${\mathrm{T}}_{10}=a+9d=11+9\left(20\right)=191$