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Q.

The 10th term of the sequence $\sqrt{2}, \sqrt{8}, \sqrt{18}, \dots$ is

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a

\sqrt{288}

b

\sqrt{200}

c

\sqrt{242}

d

\sqrt{162}

answer is B.

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Detailed Solution

Given sequence is

\sqrt{2}, \sqrt{8}, \sqrt{18}, \dots

$\sqrt{2}, 2 \sqrt{2}, 3 \sqrt{2}, \dots$

$\Rightarrow a = \sqrt{2}, d = \sqrt{2}$

$a_{10} = a + 9 d$

$= \sqrt{2} + 9 \sqrt{2}$

$= 10 \sqrt{2}$

$= \sqrt{200}$

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