The ∫1x(2+3log⁡x)dx=

∫1x(2+3log⁡x)dx Put 2+3log⁡x=t 3xdx=dt =13∫1tdt=13log⁡|t|+c=13log⁡(2+3log⁡x)+c

The ∫1x(2+3log⁡x)dx=

∫1x(2+3log⁡x)dx Put 2+3log⁡x=t 3xdx=dt =13∫1tdt=13log⁡|t|+c=13log⁡(2+3log⁡x)+c

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The $\int \frac{1}{x (2 + 3 \log x)} dx =$

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$\frac{1}{3} \log | 3 + 2 \cos x | + c$

$\frac{1}{2} \log | 3 + 3 \log x | + c$

$\frac{1}{3} \log | 2 + 3 \log x | + c$

$\frac{1}{3} \log | 2 - 3 \log x | + c$

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$\int \frac{1}{x (2 + 3 \log x)} dx Put 2 + 3 \log x = t \frac{3}{x} dx = dt \begin{array}{l} = \frac{1}{3} \int \frac{1}{t} dt \\ = \frac{1}{3} \log | t | + c \\ = \frac{1}{3} \log (2 + 3 \log x) + c \end{array}$

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The $\int \frac{1}{x (2 + 3 \log x)} dx =$