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The 21st term of the AP where first two terms are – 3 and 4 respectively, is

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137

143

–143

answer is B.

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Detailed Solution

a = - 3, a + d = 4

$\Rightarrow d = 7$

$a_{21} = a + 20 d$

$= - 3 + 20 (7)$

$= - 3 + 140 = 137$

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