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Q.

The acceleration displacement graph of a particle moving in a straight line is shown in figure. Initial velocity of the particle is zero. Find the velocity of the particle when displacement of the particle is s =12m

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a

4 m/s

b

25  m/s

c

43 m/s

d

32  m/s

answer is D.

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Detailed Solution

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Acceleration

a=v.dvdx

adx=v.dv

∫012adx=∫0vvdv=v22

v22=area under the curve

=2+12+6+4=24

v2=48v=16×3=43  m/s

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