The acceleration due to gravity at a height 1 km above the earth is the same as at a depth of below the surface of earth. Then:

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d = 2km

$d = \frac{1}{2} km$

d = 1km

$d = \frac{3}{2} km$

answer is A.

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Detailed Solution

$\begin{array}{l} g^{1} = g (1 - \frac{2 h}{R}) \to (1) with height \\ g^{1} = g (1 - \frac{d}{R}) \to (2) with depth \\ \frac{2 h}{R} = \frac{d}{R} \Rightarrow d = 2 h \\ d = 2 km \end{array}$

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