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Q.

The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on the planet B. A man jumps to a height of 2m on surface of A. What is height of the jump by the same person on B.

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a

18 m

b

6m

c

$\frac{2}{3} m$

d

$\frac{2}{9} m$

answer is A.

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Detailed Solution

Planet A $\Rightarrow g_{A} = 9 g$

Planet B $\Rightarrow g_{B} = g$

A man jumps to a height of 2m on surface of A is h = 2m

$h_{A} = \frac{u^{2}}{2 (g_{A})} = \frac{u^{2}}{2 (9 g)} = \frac{u^{2}}{18 g} = 2$

$h_{B} = \frac{u^{2}}{2 (g_{B})}$

$\frac{h_{A}}{h_{B}} = \frac{1}{9} \Rightarrow h_{B} = 9 \times h_{A} = 9 \times 2 = 18 m$

The man jumps to a height of 18m on the surface of B

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The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on the planet B. A man jumps to a height of 2m on surface of A. What is height of the jump by the same person on B.