The acceleration of a car started at t=0 , varies with time as shown  in figure the distance travelled by  the car in the 25 s is

$\begin{array}{l}\mathrm{u}=0\mathrm{t}=10\mathrm{s},\mathrm{a}=5\mathrm{m}/{\mathrm{s}}^2\\ {\mathrm{s}}_1=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2\\ =\left(0\right)\left(10\right)+\frac{1}{2}\left(5\right)\left(10\right)\\ 0+\frac{1}{2}\times 5\times 100=250\mathrm{m}\\ \mathrm{V}\text{ after }10\mathrm{s}\\ \mathrm{V}=\mathrm{u}+\mathrm{at}=0+\left(5\right)\left(10\right)=50\mathrm{m}/\mathrm{s}\\ \mathrm{v}=50\mathrm{m}/\mathrm{s},\mathrm{t}=10\mathrm{s}\\ {\mathrm{s}}_2=\mathrm{vt}=\left(50\right)\left(10\right)=500\mathrm{m}\\ {\mathrm{s}}_3=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2\\ =\left(50\right)\left(5\right)+\frac{1}{2}(-10)(5{)}^2\\ =250-5\left(25\right)=250-125=125\mathrm{m}\\ \mathrm{S}\text{ in }25\mathrm{s} \mathrm{is}={\mathrm{S}}_1+{\mathrm{S}}_2+{\mathrm{S}}_3\\ =250+500+125=875\mathrm{m}\end{array}$