The acceleration of a particle with speed v is $\mathbf{a}=\mathbf{b}\times \mathbf{v}$, where $\mathbf{b}$ is a constant vector which is neither parallel nor anti- parallel to velocity. Then,

$\mathbf{a}=\mathbf{b}\times \mathbf{v}\Rightarrow \mathbf{a}$ (acceleration) is always

perpendicular to velocity or we can say that force F is perpendicular to velocity. Hence, the work done on the particle by the force is zero, its change in kinetic energy is also zero and the speed of the particle remains constant.

Options (2) and (3) are correct.