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The active element of a certain laser is made of a glass rod 30.0 cm long and 1.50 cm in diameter. Assume the average coefficient of linear expansion of the glass is $9.00 \times 10^{- 6}^{\circ} C^{- 1}$ . If the temperature of the rod increases by ${65.0}^{\circ} C$ , what is the increase in its diameter?

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0.0028 mm

0.00356 mm

0.043 mm

0.0087 mm

answer is D.

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Detailed Solution

he increase in diameter of the rod is calculated as follows:

ΔD=DαΔT≈0.00878 mm

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