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Q.

The activity of a radioactive sample initially is 3200 dps and after 8 hrs. activity is 100 dps. What will be the activity after 4.8 hr from start in dps?

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a

150

b

400

c

200

d

300

answer is D.

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Detailed Solution

kt=ln⁡AoAt

k×8=ln⁡3200100

So,

k×4.8=ln⁡3200x (1/8)ln⁡3200100×4.8=ln⁡3200x x=400

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