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Q.

The addition of HI in the presence of peroxide does not follow anti-Markovnikov's rule because

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a

I combines with H to give back HI

b

HI is a reducing agent

c

I atom is not reactive enough to add on a double bond

d

HI bond is too strong to be broken homolytically

answer is B.

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Detailed Solution

Iodine free radicals are more likely to join with one another to generate iodine molecules than to attack double bonds because the H-I bond, which they are formed from, is weaker.

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