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The adjacent sides of a parallelogram ABCD measures 34 cm and 20 cm and the diagonal AC measures 42 cm. find the area of the parallelogram.

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600

{cm}^{2}

550

{cm}^{2}

672

{cm}^{2}

772

{cm}^{2}

answer is C.

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Detailed Solution

△ ACD

S = \frac{20 + 34 + 42}{2} = 48

Area of

△ ACD = \sqrt{48 \times 28 \times 14 \times 6} = 336

∵

Diagonal divides parallelogram in two congruent triangles
C:UserssoftberryDownloadsP0042 JPEGq50.jpg

∴

Area of ΔACD = Area of ΔBCA
Area (quad ABCD)

= 2 \times 336

= 672 {cm}^{2}

Correct option is 3.

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