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Q.

The adjoining figure represents the observed intensity of X-rays emitted by two different tubes A and B as a function of wavelength  λ. For the tube A, the potential difference  between the filament and target is  VA  and atomic number of target is ZA  For the tube B,  corresponding potential difference is VB  and the atomic number is ZB . The solid curve is for  tube A and dotted curve for tube B; then :
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a

ZA>ZB;VA>VB

b

ZA=ZB;VA=VB

c

ZA<ZB;VA<VB

d

ZA<ZB;VA>VB

answer is D.

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Detailed Solution

From the figure, the cut-off wave length of A is less so the applied voltage of A is more. 
Since λ1V  .The wavelength of K  line is less for B so its atomic no is more 
Since  λ1(Zb)2

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