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Q.

The alcoholic structure of 2-butane is given by the formula:

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a

CH3CH2CH2CH2OH 

b

CH3CH2OHCH2CH3

c

CH3CH2CH2OCH2

d

CH3CH2CH2OCH2

answer is C.

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Detailed Solution

H3C–CH2–CH2–CH3 -> Butane

H3C–CH2–CH2–CH2–OH -> 1-Butanol

H3C–CH2–CH2–CH3 -> 1-Butanol

|

OH

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The alcoholic structure of 2-butane is given by the formula: