The alkaline ${CuSO}_{4}$ , containing sodium potassium tartrate does not react with

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$C_{6} H_{5} CHO$

$C_{6} H_{5} {CH}_{2} CHO$

${CH}_{3} CHO$

$C_{2} H_{5} CHO$

answer is D.

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Detailed Solution

The alkaline CuSO₄, containing sodium potassium tartrate is Fehling solution and in aromatic aldehydes, the CHO group is attached to a benzene ring.
Due to resonance, carbonyl group's C acquires a double bond character with the benzene, which is very strong to break.
Oxidizing agents like Cu²⁺ are unable to break that bond, so such aldehydes are unable to show fehling's test.
Thus, C₆H₅CHO does not react with the alkaline CuSO₄, containing sodium potassium tartrate.

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