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The AM of 30 students is 42. Among them two got zero marks, then AM of remaining students is

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answer is C.

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Detailed Solution

$= n 2 n + 1 6$

Sum of marks

$x 1, x 2, x 3, ⋯ x n$

$= n n + 1 2 n + 1 n + 1 × 6$

of remaining students

$x ¯$

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