The ammonia evolved by the treatment of 0.30g of an organic compound for the estimation of nitrogen was passed in 100 ml of 0.1M sulphuric acid. The excess of acid required 20mL of 0.5M solution hydroxide solution for complete neutralization. The organic compound is

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benzamide

thourea

urea

acetamide

answer is C.

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Detailed Solution

Excess of acid = 20 × 0.5 × 1 m.e.q
Acid taken initially = 100 × 0.1 × 2 m.e.q
Acid used for neutralisation
$\begin{array}{l} (100 \times 0.1 \times 2) - (20 \times 0.5 \times 1) \\ 20 - 10 = 10 m.eq. \end{array}$
$\Rightarrow$ NH₃ liberated =10 m.eq.
$\begin{array}{l} % N = \frac{{NH}_{3} liberated (m . eq)}{wt . of org . compound} \times 1.4 \\ = \frac{10 \times 1.4}{0.3} = 46.66 % \end{array}$
Urea has 46.66% N

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