The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $N i C l_{2} .6 H_{2} O$ to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of $N i C l_{2} .6 H_{2} O$ are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is………
(Atomic weights in $g m o l^{- 1} : H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59$ )

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answer is 2992.

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Detailed Solution

${(N H_{4})}_{2} S O_{4} + C a {(O H)}_{2} \overset{}{\to} \underset{G y p s u m (M = 172) 12 m o l e}{C a S O_{4} .2 H_{2} O} + \underset{24 m o l e}{2 N H_{3}}$

$\underset{952 g = 4 m o l}{N i C l_{2} .6 H_{2} O} + \underset{24 m o l}{6 N H_{3}} \overset{}{\to} \underset{(M = 232) 4 m o l}{[N i {(N H_{3})}_{6}]} C l_{2} + 6 H_{2} O$