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The ammonia $({NH}_{3})$ released on quantitative reaction of 0.6 g urea $({NH}_{2} {CONH}_{2})$ with sodium hydroxide (NaOH) can be neutralized by

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100 mL of 0.2 N HCl

100 mL of 0.1 N HCl

200 mL of 0.4 N HCl

200 mL of 0.2 N HCl

answer is A.

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Detailed Solution

2 × mole of Urea mole of ${NH}_{3}$ …..(1)

Mole of ${NH}_{3}$ = mole of HCl …..(2)

$∴$ mole of HCl = 0.02 mole

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