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The amount energy required to form a soap bubble of radius 2 cm from a soap solution is nearly: (surface tension of soaps solution = 0.03 Nm^-1)

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30.16 × 10^–4 J

5.06 × 10^–4 J

3.01 × 10^–4 J

50.1 × 10^–4 J

answer is D.

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Detailed Solution

U= surface tension x surface area Soap bubble has 2 surfaces
$U = T \times 2 (4 π R^{2}) = 8 π R^{2} T$
$= 8 \times π \times {(2 \times 10^{- 2})}^{2} \times 0.03$
$= 3.01 \times 10^{- 4} J$

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