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The amount of calcium oxide obtained by heating 25kg of calcium carbonate (80% pure) is

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14kg

11.2kg

7kg

5.6kg

answer is B.

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Detailed Solution

Given weight of calcium carbonate

= 25 k g = 25000 g

$C a C O_{3} \to C a O + C O_{2}$

$100 g 56 g 44 g$

100g of CaCO3 produces 56g of purity of $C a C O_{3} = 80 %$

So, actual weight of $C a C O_{3} = \frac{80}{100} \times 25000 = 20000 g$

Therefore, 20000g of calcium carbonate will produce calcium oxide

$= \frac{56}{100} \times 20000 = 11200 g o r 11.2 k g$ .

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