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The amount of charge in F (Faraday) required to obtain one mole of iron from ${Fe}_{3} O_{4}$ is _____. (Nearest Integer)

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answer is 3.

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Detailed Solution

${Fe}_{3} O_{4} \equiv FeO . {Fe}_{2} O_{3} \equiv {Fe}^{2 +} + 2 {Fe}^{3 +} + 8 e^{-} \to 3 Fe$
$3 mol Fe require 8 F charge 1 mol Fe require \frac{8 F}{3} charge = 2.67 F \approx 3 F$

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