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The amount of chlorine evolved when 2 amperes of current is passed for 30 minutes in an aqueous solution of NaCl

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66 g

1.32 g

33 g

99 g

answer is B.

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Detailed Solution

Time (t) = 30 min =30 x 60 sec

Current (i) = 2 amp

Q= it

= 2 X 30 X 60 = 3600 c

now , since 96500 c of charge deposits 35.5 g of chlorine .

Thus , 3600c charge will deposit = $\frac{35.5}{96500} \times 3600 = 1.32 g$

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