The amount of chlorine evolved when 2 amperes of current is passed for 30 minutes in an aqueous solution of NaCl

$$\begin{gathered} Current i is equal to 2 amps. \\ and \text{ time }=30\text{ minutes }=30\times 60\text{ seconds } \\ Faraday\text{'}s First Law states: \\ \begin{array}{l}\Rightarrow m=\text{ Eit }\\ \Rightarrow m=\frac{\text{ Eit }}{96500}\to \left(1\right)\end{array} \\ \text{ Here, }E=\frac{\text{ Atomic Mass }}{\text{ Valency }} \\ Chlorine\text{'}s atomic mass is 35.5 \\ Valency of Chlorine=1 \\ \mathrm{E}=\frac{35.5}{1}=35.5 \\ Chlorine\text{'}s atomic mass is 35.5 \\ When all values are entered into equation 1- \\ \begin{array}{l}m=\frac{35.5\times 2\times 30\times 60}{96500}\\ m=1.324g\end{array} \\ Chlorine evolved in an amount of 1.324g. \end{gathered}$$

Therefore, the correct option is B