The amount of electricity that can deposit 108 g of Ag from AgNO₃ solution is:

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1 F

2 A

1 C

1 A

answer is A.

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Detailed Solution

According to Faraday law's of electrolysis, amount of electricity required to deposit 1 mole of metal = 96500 C = 1 F
i.e., for deposition of 108g Ag electricity required = 1 F

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